Monday, September 26, 2011

Blog Post 4D

Let f(x) = 2|x-2|+ 1. Remember the absolute value graph has a V-Shape.

Graph this on your own, and write it as a piecewise function.

2 comments:

  1. So to find the piecewise function we have to do a few steps:
    1.Anything that is greater than x = 2 would mean that we're basically graphing y = 2(x - 2) + 1. Getting it into y-intercept form, we get:
    y = 2(x - 2) + 1
    y = 2x - 4 + 1
    y = 2x - 3
    2.Anything that is less than x = 2 would mean that we're graphing y = 2[-(x - 2)] + 1 - the opposite of the absolute value Simplifying, we get:
    y = 2[-(x - 2)] + 1
    y = -2x + 4 + 1
    y = -2x + 5
    3.So, the piecewise functions are:
    y= (2x+1), x≥2
    y=(-2x+5),x <2

    ReplyDelete
  2. Thank you for being the one person who tried this problem. Did anybody have any thoughts on the answer provided. It would be nice to have some feedback.

    ReplyDelete